Findthe are of a rhombus whose altitude is 4cm and perimeter is 36cm
Answers
We need to get the length of the rhombus
A rhombus has four equal sides.
The perimeter is :
4l where l is the length of the sides.
We want l:
4l = 36
l = 36/4 = 9
The length of the sides is thus 9cm
Area is:
A = length × altitude (height)
= 9 × 4 = 36 cm²
36 cm² is the area of a rhombus whose altitude is 4 cm and perimeter is 36 cm
Given : a rhombus whose altitude is 4 cm and perimeter is 36 cm.
To Find : Area of a rhombus
Solution:
Properties of Rhombus :
All Sides are equal
Diagonals bisects each other perpendicularly
Let say side length of Rhombus = a cm
Perimeter of Rhombus = 4a cm
Perimeter of the rhombus = 36 cm
Equate Perimeter
=> 4a = 36
=> a = 9 cm
Area of Rhombus = side * altitude
= 9 x 4
= 36 cm²
Hence area of the rhombus is 36 cm²
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