findthe distance between the pair of points (2,3) ,. (4,1)
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Answered by
1
The formula is the square root of sim of squares of difference in abscissa and ordinate.
=> Ans = √{(4-2)^2+(1-3)^2} =√(4+4 = √8 = 2√2
=> Ans = √{(4-2)^2+(1-3)^2} =√(4+4 = √8 = 2√2
Answered by
1
let A = ( 2,3)
B = ( 4,1)
distance between A and B =
underroot (4-2)^2 + (1-3)^2
= 2 root 2
B = ( 4,1)
distance between A and B =
underroot (4-2)^2 + (1-3)^2
= 2 root 2
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