findthe HCF of the following 256, 442 and 940
Answers
Answered by
13
Given:
3 numbers : 256, 442 and 940
To Find:
The HFC of the 3 numbers
Solution:
Find the product of its prime factors of 256:
256 = 2 x 2 x 2 x 2 x 2 x2 x 2 x 2
256 = 2⁸
Find the product of its prime factors of 442:
442 = 2 x 13 x 17
Find the product of its prime factors of 940:
940 = 2 x 2 x 5 x 47
940 = 2² x 5 x 47
Find the HFC of the 3 numbers:
256 = 2⁸
442 = 2 x 13 x 17
940 = 2² x 5 x 47
HFC is the common prime factors among the 3 numbers
⇒ HFC = 2
Answer: The HFC is 2
Answered by
3
Answer:
3 numbers : 256, 442 and 940
To Find:
The HFC of the 3 numbers
Step-by-step explanation:
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