Question

Findthe no of valence electrons present in 0.53 g of na2co3

Answer 1

Molar mass of Na2CO3​ = 106 gmol-1

No. of moles = Given mass Molar mass= 53106 = 0.5 mol

As, Na2CO3 is an ionic compound, so Na will lose electrons and CO32-  will gain electrons.
​No. of electrons in 1 molecule of  Na2CO3 = 2×10 (Na+) + [6+(8×3)+2 ](CO32-)  
                                                                    = 20+ 32 = 52 electrons

No. of electrons in 1 mole of ​Na2CO3 = 52×6.022×1023
                                                             = 3.13×1025
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