findthe sum of an AP 2.7.12 to 25 terms
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Answer:
A.P.=Sn=n/2[2a+(n-1)d]
a=2,d=7-2=5,n=25
S10=25/2[2×2+(25-1)5]
=25/2[4+120]
=25/2×124
=1550
therefore the sum of 25 terms is 1550
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