Question

findthe value of k, if (x-1) is a factor of p(x)=kx^2-2x+1​

Answer 1

Answer:

3 right answer

Step-by-step explanation:

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Answer 2

Given :-

• (x - 1) is a factor of kx² - 2x + 1

To find :-

The value of k = ?

Solution:

Since (x - 1) is a factor, apply factor theorem by equating factor to zero.

(x - 1) = 0

→ x = 1

Substitute the value of x in p(x) to find the remainder. Since (x - 1) is a factor, the remainder will obviously be zero.

p(x) = kx² - 2x + 1

p(1) = k(1)² - 2(1) + 1

→ p(1) = k - 2 + 1

→ p(1) = k - 1

This (k - 1) will be equal to zero.

k - 1 = 0

→ k = 1

∴ The value of k = 1