Question

Findthesquareofthefollowingnumbers:

a)81​

Answer 1

Step-by-step explanation:

Solution:-

${81}^{2} = (80 + 1) ^{2} \\ = {80}^{2} + 2(80)(1) + {1}^{2} \\ = 6400 + 160 + 1 \\ = 6561 \\ \\ the \: formula \: used \: here \: is \\ {( x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$

Answer 2

Step-by-step explanation:

The solution has been attached.

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