Question

Findvthe least number when divided by 5,9,12and 20in each case leaves remainder of 3

Answer 1

Step 1 : Find the LCM of the numbers

5 = 5 × 1

9 = 3 × 3

12 = 2 × 2 × 3

20 = 2 × 2 × 5

LCM = 180


Step 2 : Add 3 to the LCM

180 + 3 = 183


∴ The least number which when divided by 5, 9, 12 and 20 leaves a remaider in each case is $\bold{183}$


Let's divide and check :

$\dfrac{183}{5}$ ➾ Quotient = 36 and Remainder = 3


$\dfrac{183}{9}$ ➾ Quotient = 20 and Remainder = 3


$\dfrac{183}{12}$ ➾ Quotient = 15 and Remaider = 3


$\dfrac{183}{20}$ ➾ Quotient = 9 and Remainder = 3



∴ The least number which when divided by 5, 9, 12 and 20 leaves a remaider in each case is $\bold{183}$



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Answer 2

here is your answer

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we know that a easy that a lcm
so...............

5 = 5 × 1

9 = 3 × 3

12 = 2 × 2 × 3

20 = 2 × 2 × 5

LCM = 180

so in given remainder 3 so add

180 + 3 = 183

answer is 183

$\huge \: {thanks}$

that check so all in 3 remainder OK