Question

fine 2nd and 3rd term of the sequence whose nth term give by tn=2n-5.

Answer 1

Tn = 2n - 5
a+(n-1) d = - 3 + 2 n - 2
=> a +(n-1) d = - 3 + 2(n-1)

Comparing both sides, we get
a= - 3
d= 2

T2 = a+d = - 3 + 2= - 1
T3 = a+2d = - 3 + 4 = 1


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Answer 2

let n=1
T1=2×1-5=2-5=-3
let n=2
T2=2×2-5=4-5=-1
let n=3
T3=2×3-5=5-5=1
so second and third term of the sequence is -1 and 1
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