Question

Fine all possible values of y for which the four digit number 6x4y3 is divisible by 3.​

Answer 1

Step-by-step explanation:

We know that the given number

18x71

is divisible by 3.

And, if a number is divisible by 3 then sum of digits must be a multiple of 3.

i.e., 1+8+x+7+1= multiple of 3

x+17=0,3,6,9,12,15…

Here x is a digit, where, x can have values between 0 and 9.

x+17=18 which gives x=1.

x+17=21 which gives x=4.

x+17=24 which gives x=7.

Hence, x=1,4,7.