Question

Fine the 9th term of the series 6,11,16,21,26

Answer 1

Given Sequence is

6 , 11 , 16 , 21 , 26

We Get

First term (a) = 6

Common Difference (d) = a₂-a₁ = 11 - 6 = 5

Formula

Tₙ = a + ( n - 1 )d

Now Put the Value on formula

T₉ = 6 + (9 - 1)5

T₉ = 6 + 8×5

T₉ = 6 + 40

T₉ = 46

Answer

T₉ = 46

More Formula Of AP

General term of AP

Tₙ = a + ( n - 1 )d

Sum of first term in AP

Sₙ = n/2{2a + (n - 1)d

nth term from end

{l - (n - 1)d}

middle term

(n+1)/2 term

First middle term

n/2 term

Second middle term

(n/2) + 1