Fine the area of a square inscribed in a circle of radius 8cm
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Answered by
5
Step-by-step explanation:
Given,
Radius = r=8cm
∵ The diagonals of square subtend right angle at circumference.
∴The diagonals of square are diameters of circle.
BD = 2*8 = 16cm
Let the sides of square be 'x' cm
in the right angle triangle BCD,
BC² +CD² = BD²
x² + x² = 16²
2x² = 256
x² = 128
Thus the area of square is x² = 128cm²
Answered by
0
Hey there!
Given,
Radius of circle = 8 cm
Diameter = 2 * r = 16 cm
Here, The diameter of circle = diagonal of square = 16 cm
Then, Area of square = diagonal^2/2
= 16^2/2
= 256/2
= 128 cm²
Good day!
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