Question

Fine the area of triangle 150cm,120cm,200cm

Answer 1

⇝Given :-

➳Sides of triangle :

• 1st side = 150cm
• 2nd side = 120cm
• 3rd side = 200cm

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⇝To Find :-

• Area = ?

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⇝Formula Used :-

➳Area of triangle :

${\red{\maltese{\orange{\boxed{\mathfrak{\pink{{Area = \sqrt{s(s - a)(s - b)(s - c)} }}}}}}}}{\red{\maltese}}$

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⇝Solution :-

❒Here,

• 1st side = 150cm
• 2nd side = 120cm
• 3rd side = 200cm

❒Solving starts,

${\mapsto{\bf{S = \frac{a + b + c}{2} }}}$

${\twoheadrightarrow{\bf{S = \frac{150+ 120 + 200}{2} }}}$

${\twoheadrightarrow{\bf{S = {\cancel \frac{470}{2} }}}}$

${\blue{\dashrightarrow{\red{\underline{\bf{Semi - Perimeter = 235 cm}}}}}}$

❒Than,

${\mapsto{\bf{{Area = \sqrt{s(s - a)(s - b)(s - c)}}}}}$

${\twoheadrightarrow{\bf{{Area = \sqrt{235(235 - 150)(235 - 120)(235- 200)}}}}}$

${\twoheadrightarrow{\bf{{Area = \sqrt{235 \times 85 \times 115 \times 35}}}}}$

${\large{\blue{:{\longmapsto{\pink{\underline{\boxed{\pmb{\bf{8966.57 cm² }}}}}}}}}}$

❒So,

${\red{\underline{\green{\underline{\purple{\boxed{\red{\mathfrak{Area = 8966.57 \: cm² }}}}}}}}}$

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Answer 2

Answer:

$⇝Given :-</p><p></p><p>➳Sides of triangle :</p><p></p><p>1st side = 150cm</p><p></p><p>2nd side = 120cm</p><p></p><p>3rd side = 200cm</p><p></p><p>▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃</p><p></p><p>⇝To Find :-</p><p></p><p>Area = ?</p><p></p><p>▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃</p><p></p><p>⇝Formula Used :-</p><p></p><p>➳Area of triangle :</p><p></p><p>{\red{\maltese{\orange{\boxed{\mathfrak{\pink{{Area = \sqrt{s(s - a)(s - b)(s - c)} }}}}}}}}{\red{\maltese}}✠Area=s(s−a)(s−b)(s−c)✠</p><p>▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃</p><p></p><p>⇝Solution :-</p><p></p><p>❒Here,</p><p></p><p>1st side = 150cm</p><p></p><p>2nd side = 120cm</p><p></p><p>3rd side = 200cm</p><p></p><p>❒Solving starts,</p><p></p><p>{\mapsto{\bf{S = \frac{a + b + c}{2} }}}↦S=2a+b+c</p><p>{\twoheadrightarrow{\bf{S = \frac{150+ 120 + 200}{2} }}}↠S=2150+120+200</p><p>{\twoheadrightarrow{\bf{S = {\cancel \frac{470}{2} }}}}↠S=2470</p><p>{\blue{\dashrightarrow{\red{\underline{\bf{Semi - Perimeter = 235 cm}}}}}}⇢Semi−Perimeter=235cm</p><p></p><p>❒Than,</p><p></p><p>{\mapsto{\bf{{Area = \sqrt{s(s - a)(s - b)(s - c)}}}}}↦Area=s(s−a)(s−b)(s−c)</p><p>{\twoheadrightarrow{\bf{{Area = \sqrt{235(235 - 150)(235 - 120)(235- 200)}}}}}↠Area=235(235−150)(235−120)(235−200)</p><p>{\twoheadrightarrow{\bf{{Area = \sqrt{235 \times 85 \times 115 \times 35}}}}}↠Area=235×85×115×35</p><p>{\large{\blue{:{\longmapsto{\pink{\underline{\boxed{\pmb{\bf{8966.57 cm² }}}}}}}}}}:⟼8966.57cm²8966.57cm²</p><p></p><p>❒So,</p><p></p><p>{\red{\underline{\green{\underline{\purple{\boxed{\red{\mathfrak{Area = 8966.57 \: cm² }}}}}}}}}Area=8966.57cm²</p><p>▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃</p><p>$