Fine the remainder when
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Answer:
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Question :-
Find the remainder when x³ - 3x² + 3x + 1 divided by 2x + 5.
Answer :-
Solution :-
Given -
- dividend = x³ - 3x² + 3x + 1
- divisor = 2x + 5
To Find -
- remainder
Process -
(x²/2) - (11/4)x + (67/8)
______________
2x + 5 ) x³ - 3x² + 3x + 1 (
x³ + (5/2)x²
- -
_________
0 -(11/2)x² +3x +1
-(11/2)x² -(55/4)x
+ +
_____________
0 + (67/4)x + 1
+ (67/4)x + (335/8)
- -
_______________
0 - (327/8)
_______________
___________
Hence the remainder obtained is - 327 / 8 .
___________
. .