Question

fine the value i Power 49+ i power 68+i power 89+i power 110​

Answer 1

Answer:

${i}^{49} + {i}^{68} + {i}^{89} + {i}^{110} \\ = {i}^{48} \times i+ {i}^{68} + {i}^{88} \times i+ {i}^{110} \\ = ( {i}^{2} )^{24} \times i + ( {i}^{2} )^{34} + ( {i}^{2} )^{44} \times i + ( {i}^{2} )^{55} \\ = ( - 1)^{24} \times i + ( - 1)^{34} + ( - 1)^{44} \times i + ( - 1)^{55} \\ = 1 \times i + 1 + 1 \times i + ( - 1) \\ = i + 1 + i - 1 \\ = 2i$

$\because i^2 =-1$

Answer 2

Answer:

2i

Step-by-step explanation:

i^48 × i + i^68 + i^88 ×i + i^110

(i^2)^24 ×i +( i^2)^34+ (i^2)^44 ×i + (i^2)^55

1×i + 1+i-1

2i