Question

fine the value :

lim sin`¹x/x
x➡0​

Answer 1

Step-by-step explanation:

$lim \: \: \: \: sin^{ - } \frac{x}{x} \\ x = > 0 \: \: \: \\ = > sin0 = 90 {}^{o}$

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Answer 2

Answer:

hi❤gm

sin`¹x=z :. x=sinz

if, x➡0 then, z➡0

: .lim sin`¹x/x

x➡0

lim z/sinz =1/lim sinz/z =1/1 =1

z➡0 z➡0

hope it's helpful ⭐