Math, asked by mangeshshirbhate, 11 days ago

fine the value of 3a+4b+5c when a=1,b=0,c=1​

Answers

Answered by TrAnSLIMit
0

Answer:

8

Step-by-step explanation:

3a + 4b + 5c

Substituting a = 1, b = 0, c = 1, then,

3 \times 1 + 4 \times 0 + 5 \times 1 \\  = 3 + 0 + 5 \\  = 8

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Answered by alex971
0

Answer:

8

Step-by-step explanation:

3a+4b+5c

3*1+4*0+5*1

3+0+5

8

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