Math, asked by sujit9202, 8 months ago

Fine the zeroes of the quadratic polynomial 6xsquare -3-7x

Answers

Answered by amuu11

0

6x^2-7x-3

6x^2+2x-9x-3x

2x(3x+1) -3x(3x+1)

(2x-3x) (3x+1) ()

Answered by divya3718

0

Answer:

x=-1/2&3/2

Step-by-step explanation:

6x^2-7x-3

6x^2-9x+2x-3

(6x^2-9x)+(2x-3)= 3x(2x-3)+1(2x-3)

(3x+1)(2x-3)=x=-1/2&3/2

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