Question

fine two consecitive positive integer sum of whose square is 365. answer fastttt i will mark as brainlist

Answer 1

let the 2 consecutive positive integers be x and x+1

According to the question,

x^2+(x+1)^2=365

x^2+x^2+1+2x=365

2x^2+2x+1=365

By factorization using the splitting the middle term,

2x^2+2x-364=0

2(x^2+x-182)=0

x^2+x-182=0

x^2-13x+14x-182=0

x(x-13)+14(x-13)=0

(x-13)(x+14)=0

Therefore , x=13,-14.

Since it was given positive integer in the question, x=13.

x+1=13+1=14

Hope this helps..pls mark brainlist!!

Answer 2

Step-by-step explanation:

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