Question

fine volume of iron used if inner radius is 20cm and thickness of sphere is 1cm

Answer 1

Answer:

Inner radius = 20 cm

Thickness = 1 cm

Outer radius = 20 + 1 = 21 cm

Volume of iron used = Volume of larger sphere - Volume of smaller sphere

= $\tt{\frac{4}{3} \pi (R^{3} - r^{3})}$

= 4/3 × 22/7 × (21^3 - 20^3)

= 4/3 × 22/7 × 1261

= $\underline{\underline{\sf{480.38 \:cu\: cm}}}$

Hope it Helps!! :)

Answer 2

Answer:

Refer to the attachment