Question

Finf ci and a when p is rs 15625 time is 2 1/4 years and r is 16% pa compounded anually

Answer 1

Solution

┻━┻┻━┻┻━┻┻┻━┻ ┻━┻

Given,

P = ₹ 1 5 6 2 5

$t = 2 \frac{1}{4}$

R = 1 6 % p. a.

Now,

$amount = p \times (1 + \frac{r}{100} ) {}^{2} \times (1 + \frac{ \frac{1}{4} \times r }{100} )$

$= 15625 \times (1 + \frac{16}{100} ) {}^{2} \times (1 + \frac{16}{400} )$

$= 15625 \times ( \frac{100 + 16}{100} ) {}^{2} \times ( \frac{400 + 16}{400 }$

$= 15625 \times ( \frac{116}{100} ) {}^{2} \times ( \frac{416 }{400} )$

$= 15625 \times \frac{116}{100} \times \frac{116}{100} \times \frac{416}{400}$

$= 21866$

Amount = ₹ 21866

CI = A – P

= ₹ ( 2 1 8 6 6 – 1 5 6 2 5 )

= ₹ 6 2 4 1

—————————————————————
I hope it will help you
———————-——-----—--———-——-——-