Question

Finf the area of sector & minor segment of a circle with radius 7cm if area of sector 60° (3marks)

Answer 1

Step-by-step explanation:

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Answer 2

25.666 , 4.449

Step-by-step explanation:

Given:

radius = 7 cm

Angle(Ф) = 60°

Area of Sector = Ф/360 x $\pi r^2$ , where $\pi = 22/7$

= 60/360 x 22/7 x 7 x 7

= 1/6 x 22 x 7

= 154 / 6

= 25.666 $cm ^2$

Area of segment = Ф/360 x $\pi r^2$ - 1/2 sinФ r²

= (60/360 x 22/7 x 6 x 6) - 1/2 $(\frac{\sqrt{3} }{2} )$ x 7 x 7

= 25.666  - 1/2 x 1.732/2 x 49

= 25.666 - 21.217

= 4.449$cm^2$

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