Question

finf the equation of the line passing through the point (1,4) and intersecting the line x-2y-11=0 on the y-axis.(answer with explanation)​

Answer 1

Answer:

FOLLOW ME

$follow \: me$

Step-by-step explanation:

equation 1 is ?

equation 2 is x-2y-11=0

the coordinates of the intersecting point belongs to both equations.

At y-axis,x=0. Putting it in eq 2,

0-2y-11=0

-2y=11

y= -11/2

So intersecting coordinate is (0, -11/2)

gradient(m)= (y1-y2)/(x1-x2)

={(-11/2)-4}/(0-1)

=19/2

Now put the values in the equation of straight line which is,

y-y1=m(x-x1),,,,, y1,x1 are coordinates on eq 1, m is the gradient of eq 1

y-4=(19/2)(x-1)

2y-8=19x-19

2y=19x-19+8

2y=19x-11 (ans)