Question

finf the hcf by prime factorization method 9,27,49​

Answer 1

Answer:

1

Step-by-step explanation:

9=3*3*1

27=3*3*3*1

49=7*7*1

H. C. F=1( common number is 1)

Answer 2

Given: The numbers are$9,27,\ and\ 49$.

We have to find the HCF of the above numbers.

As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are$9,27,\ and\ 49$.

The factors of $9$ are: $1, 3, 9$

The factors of $27$ are: $1, 3, 9, 27$

The factors of $49$ are:$1, 7, 49$

From the above, we can see that the greatest common factor is$1$.

Hence, the HCF of the above numbers is$1$.