Question

finf the hcf of (x+2)² (x+3)³ (x+5)⁴ and(x+3)² (x+4)³ (x+5) by splitting the middle term
step-by-step explanation
not direct answer❌
urgent, will mark as brainliest​

Answer 1

Answer:

Step 1 :

First, divide f(x) by g(x) to obtain

f(x) = g(x)q(x)+ r(x)

where q(x) is the quotient and r(x) is remainder,

so, deg (g(x)) > deg (r(x))

If the remainder r(x) is 0, then g(x) is the GCD of f(x) and g(x).

Step 2 :

If the remainder r(x) is non-zero, divide g(x) by r(x) to obtain

g(x) = r(x) q(x)+ r1(x)

where r1(x) is the remainder.

So, deg r(x) > deg r1(x)

If the remainder r1(x) is 0, then r(x) is the required GCD.

Step 3 :

If r1(x) is non-zero, then continue the process until we get zero as remainder.

The remainder in the last but one step is the GCD of f(x) and g(x).

We write GCD(f(x), g(x)) to denote the GCD of the polynomials f(x) and g(x).