Question

finf the point on the x-axis which is equidistant from the points (5,4) and (-2,3).Please answer quickly.​

Answer 1

Answer:

AC=BC (Equidistance)

AC2=BC2

(x−5)2+(0−4)2=(x+2)2+(0−3)2

x2−10x+25+16=x2+4+4x+9

−14x+41−13=0

−14x+28=0

=14x=−28

x=28/14x=2

These the coordinates are (2,0)



Answer 2

$\huge{ \pink{ \bold{ \boxed{ \star{(2.0)}}}}}$