Question

finf the sum of all three digit number which are divisible by 3 but not by 5

Answer 1

Answer:

Step-by-step explanation:

Answer 2

All three digit numbers which are divisible by 3 are 102,105,108,...,999.

first term=a=102

common different =105-102=3

108-105=3

Therefore it is an AP.

Un=a+(n-1)d (last term)

999=102+(n-1)3

999-102=(n-1)3

897=3n-3

900=3n

100=n

Sn=n/2{2a+(n-1)d}

S100=100/2{2x102+(100-1)3}

=50{204+99x3}

=25050

Answer the half.

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