Finf the sum of first 100 natural numbers
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Answer:
Step-by-step explanation:
n=100
a=1
d=1
Sn=n/2(2a+(n-1)d)
Sn=100/2[2x1+(100-1)x1]
=50[2+99]
=50x101
=5050
Therefore, the sum of first 100 natural numbers is 5050!!
Hope it helps y'all
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