Question

Finf three consecutive numbers whose sum shall equal 84​

Answer 1

Let the first be n , and if they are consecutive then the next two numbers are n+1 and n+2.

n+(n+1)+(n+2)=84.

3n+3=84.

⇒3n=81.

⇒n=27.

Hence numbers are n,n+1,n+2→27,28 and 29

Answer 2

Answer:

let the 3 numbers be x,x+1,x+2

Step-by-step explanation:

acco. to the question

x + (x+1) + (x+2) = 84

3x + 3 = 84

3x = 84-3

x = 81÷3

x= 27

x= 27

x+1= 28

x+2 = 29