Question

fing 2 consecutive odd integers such that two fifth of the smaller exceeds two ninth of greater by 4

Answer 1

Let the two consecutive no.s be x and x+2

According to the question-

2x/5 = 2/9( x+2) + 4

2x/5 = 2x/9 + 4/9 + 4

2x/5 - 2x/9 = 40/9

(18x - 10x)/45 = 40/9

8x = 200

x = 200/8 = 25

Therefore the two consecutive positive odd no.s are 25 and 27

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