Question

finnd the sum of the roots of quadratic equation
x²-6x+5=0​

Answer 1

Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

−

6

+

5

=

0

x^{2}-6x+5=0

x2−6x+5=0

=

1

a={\color{#c92786}{1}}

a=1

=

−

6

b={\color{#e8710a}{-6}}

b=−6

=

5

c={\color{#129eaf}{5}}

c=5

=

−

(

−

6

)

±

(

−

6

)

2

−

4

⋅

1

⋅

5

√

2

⋅

1