Question

Finnd value of k in equtionx2-2(k+1)x+k2=0 has equal root .m

Answer 1

Step-by-step explanation:

if roots are equal then b²-4ac=0

a=1 b= -2k-2 c=k²

therefore (-2k-2)²-4*1*k²=0

4k²-8k+4-4k²=0

4k² gets cancelled

-8k=-4

k=-4/-8

k=1/2