Question

fins the distance between the pair of points ((a+b),(a-b)),((a-b),(-a-b))​

Answer 1

1

1

1 ,y

1 ,y 1

1 ,y 1

1 ,y 1 )

1 ,y 1 )and (x

1 ,y 1 )and (x 2

1 ,y 1 )and (x 2

1 ,y 1 )and (x 2 ,y

1 ,y 1 )and (x 2 ,y 2

1 ,y 1 )and (x 2 ,y 2

1 ,y 1 )and (x 2 ,y 2

(x

(x 2

(x 2

(x 2 −x

(x 2 −x 1

(x 2 −x 1

(x 2 −x 1 )

(x 2 −x 1 ) 2

(x 2 −x 1 ) 2 +(y

(x 2 −x 1 ) 2 +(y 2

(x 2 −x 1 ) 2 +(y 2

(x 2 −x 1 ) 2 +(y 2 −y

(x 2 −x 1 ) 2 +(y 2 −y 1

(x 2 −x 1 ) 2 +(y 2 −y 1

(x 2 −x 1 ) 2 +(y 2 −y 1 )

(x 2 −x 1 ) 2 +(y 2 −y 1 ) 2

(x 2 −x 1 ) 2 +(y 2 −y 1 ) 2

(x 2 −x 1 ) 2 +(y 2 −y 1 ) 2

(x 2 −x 1 ) 2 +(y 2 −y 1 ) 2

(a−b−a−b)

(a−b−a−b) 2

(a−b−a−b) 2 +(c−b−b−c)

(a−b−a−b) 2 +(c−b−b−c) 2

(a−b−a−b) 2 +(c−b−b−c) 2

(a−b−a−b) 2 +(c−b−b−c) 2

(a−b−a−b) 2 +(c−b−b−c) 2 =

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b 2

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b 2

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b 2

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b 2 =2

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b 2 =2 2

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b 2 =2 2

(a−b−a−b) 2 +(c−b−b−c) 2 = 4b 2 +4b 2 =2 2 b