Question

fins the distance between the points (-1,5) and (5,5)

Answer 1

d²=(x-x1)²+(y-y¹)²
d²= (5+1)²+(5-5)²
d²=(6)²+(0)²
d²=36
d=6 units

Answer 2

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Topic:- CO-ODINATE GEOMETRY

Topic:- Distance based Question

Here,

We have;

x1=-1, y1=5,x2=5,y2=5

According to the Formula!

$PQ = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$PQ = \sqrt{(5 - ( - 1))^2+(5 - 5)^2}$
$PQ = \sqrt{(6)^2+(0)^2}$
$PQ = {(6)}^{2} = \sqrt{36}$

$\bold{pq = 6 \: units}$

Thanks!!