fins the greatest possible no which can divi76,132,160 nd leaves remender same in each case
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0
Answer:
The Greatest possible number that can divide 76, 132 and 160 is 4, which gives a remainder of zero in each case.
Answered by
0
Answer:
4
Step-by-step explanation:
Find HCF:
76 = 2² x 19
132 = 2² x 3 x 11
160 = 2⁵ x 5
HCF = 2² = 4
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