Question

fins the polynomial whose zerose are -2/3 and 3/2 .​

Answer 1

Answer:

ur answer

Step-by-step explanation:

> f(x) = k[x² - (A + B)x + AB]

Given that, two zeros are 3 and -2

Therefore,

Sum of the zeros (A + B) = 3 + (-2)

= 1

And,

Product of the zeros (AB) = 3*(-2)

= - 6

Therefore,

Required Polynomial,

f(x) = k[x² - 1x + (-6)]

f(x) = k[x² - x - 6]

Let k be 1,

So,

f(x) = x² - x - 6