Question

fint the derivative of the following in physics
Q. 4x³+7x²+6x+9​

Answer 1

Given ,

The function is

• y = 4x³ + 7x² + 6x + 9

Differentiating wrt x , we get

$\sf \mapsto \frac{dy}{dx} = \frac{d(4 {x}^{3} + 7 {x}^{2} + 6x + 9 ) }{dx}$

$\sf \mapsto \frac{dy}{dx} = \frac{d( 4{x}^{3} )}{dx} + \frac{d(7 {x}^{2} )}{dx} + \frac{d(6x)}{dx} + \frac{d(9)}{dx}$

$\sf \mapsto \frac{dy}{dx} = 12 {x}^{2} + 14x + 6 + 0$

Remmember :

$\sf \mapsto \frac{d(u \pm v)}{dx} = \frac{d(u)}{dx} \pm \frac{d(v)}{dx}$

$\sf \mapsto \frac{d( {x}^{n} )}{dx} = n {(x)}^{n - 1}$

$\sf \mapsto \frac{d(constant)}{dx} = 0$