Fir what value of k( -4) is a zero of the polynomial x²-2x(7p+3)
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Answer:
Where is the k inside the given question..
Step-by-step explanation:
I think p is written there instead of k.
p(x) = x² - 2x(7k + 3)
p(-4) = (-4)² -2(-4)(7k+3)
0 = 16 +8(7k+3)
0 = 16 + 56k + 24
56k = - 40
k = -40/56
k = -5/7
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