first and 5 term is 48. Find the terms of AP
3 in an AP if the 12 term is -13 and the sum of first I terms is 24. what is
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Let those integers be a-2d, a-d, a, a+d & a+2d.
By first condition, we get
3a=24.
a=8
By second condition,
(a-2d)(a+2d)=48
a^2-4d^2=48
4d^2=16
d=+2
For both values of d, you get the same integers. But for positive value, they will be in ascending order while for negative value ,they will be in descending order.
Integers= 4, 6, 8, 10 & 12.
Step-by-step explanation:
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