Question

first beaker. Find the amount of water in the jug at first.
3. Nora poured all the water from a jug into 3 beakers. The
amount of water in the first beaker was
water in the second beaker and the amount of water in the
first beaker. The third beaker has 45 ml less water than the
the amount of
First beaker. Find the amount of water in the jug at first.

Answer 1

is given that when the beaker is half full, it will float, that means weight of water and beaker is supported by upthrust. Lets say V is total volume of water displaced in the sink.

Mass of water in half filled beaker =250cm

3

×1gm/cm

3

=250gm

So applying the law of floatation, we have

weight of water and beaker = weight of water displaced in the sink

⇒(

1000

390+250

)×9.8=V×1000×9.8

⇒V=640×10

−6

m

3

=640cm

3

So volume of solid mass of beaker =640cm

3

−500cm

3

=140cm

3

And we know the mass of the beaker =390gm

⇒Density of beaker =

140cm

3

390gm

=2.7857gm/cm

3

≈2.79gm/cm

3

solution

Answer 2

Answer:

your answer in attachment...