Science, asked by wowilyt, 10 months ago

FIRST CORRECT ANSWER GETS BRAINLIEST You will drop the bottle/water mass so that it hits the lever at different speeds. Since an object in free fall is accelerated by gravity, you need to determine the heights necessary to drop the bottle to achieve the speeds of 2 m/s, 3 m/s, 4 m/s, 5 m/s, and 6 m/s. Use the equation Ht = v squared over 2 g. to calculate the height, where Ht is the height, v is the speed (velocity), and g is the gravitational acceleration of 9.8 m/s2.

Record these heights in Table B.

To achieve a speed of 2 m/s, the bottle must be dropped at
m.

To achieve a speed of 3 m/s, the bottle must be dropped at
m.

To achieve a speed of 4 m/s, the bottle must be dropped at
m.

To achieve a speed of 5 m/s, the bottle must be dropped at
m.

To achieve a speed of 6 m/s, the bottle must be dropped at
m.

Answers

Answered by prmkulk1978
74

Given :

Height necessary to drop the bottle to achieve the speeds of 2 m/s:

Hmax = u²/2g

where u= 2m/s

g= 9.8 m/s²

Hmax= 2 x2 / 2 x 9.8

=0.20 m

Height necessary to drop the bottle to achieve the speeds of 3 m/s:

Hmax = u²/2g

where u= 3m/s

g= 9.8 m/s²

Hmax= 3 x3 / 2 x 9.8

=0.46m

Height necessary to drop the bottle to achieve the speeds of 4 m/s:

Hmax = u²/2g

where u= 4m/s

g= 9.8 m/s²

Hmax= 4x4/ 2x 9.8

= 0.82m

Height necessary to drop the bottle to achieve the speeds of 5 m/s:

Hmax = u²/2g

where u= 5m/s

g= 9.8 m/s²

Hmax= 5x5/ 2 x9.8

=1.28m

Height necessary to drop the bottle to achieve the speeds of 6 m/s:

Hmax = u²/2g

where u= 6m/s

g= 9.8 m/s²

Hmax= 6x6/ 2x 9.8

= 18/9.8

=1.84m

Conclusion :

*********************************************************************************************

To acheive speed of                       Height must be

*********************************************************************************************

2m/s                                                     0.20m

3m/s                                                       0.46m

4m/s                                                       0.82m

5m/s                                                     1.28m

6m/s                                                      1.84m

********************************************************************************************

Answered by ravindrabansod26
24

Given :

Height necessary to drop the bottle to achieve the speeds of 2 m/s:

Hmax = u²/2g

where u= 2m/s

g= 9.8 m/s²

Hmax= 2 x2 / 2 x 9.8

=0.20 m

Height necessary to drop the bottle to achieve the speeds of 3 m/s:

Hmax = u²/2g

where u= 3m/s

g= 9.8 m/s²

Hmax= 3 x3 / 2 x 9.8

=0.46m

Height necessary to drop the bottle to achieve the speeds of 4 m/s:

Hmax = u²/2g

where u= 4m/s

g= 9.8 m/s²

Hmax= 4x4/ 2x 9.8

= 0.82m

Height necessary to drop the bottle to achieve the speeds of 5 m/s:

Hmax = u²/2g

where u= 5m/s

g= 9.8 m/s²

Hmax= 5x5/ 2 x9.8

=1.28m

Height necessary to drop the bottle to achieve the speeds of 6 m/s:

Hmax = u²/2g

where u= 6m/s

g= 9.8 m/s²

Hmax= 6x6/ 2x 9.8

= 18/9.8

=1.84m

Conclusion :

*********************************************************************************************

To acheive speed of                       Height must be

*********************************************************************************************

2m/s                                                     0.20m

3m/s                                                       0.46m

4m/s                                                       0.82m

5m/s                                                     1.28m

6m/s                                                      1.84m

********************************************************************************************

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