first five multiples of 3 is using AP equation
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Answer:
3,6,9,12,15
Step-by-step explanation:
Let a=3,
d=3 (because it is multiple of 3)
a1=a=3
a2=a+d=6
a3=a+2d=3+6=9
a4=a+3d=3+9=12
a5=a+4d=3+12=15
therefore, AP: 3,6,9,12,15
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