Question

First four members of homologous series beginning with ch3coch ch3oh

Answer 1

Answer:

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Explanation:

First four members of homologous series of alcohol beginning with CH3OH are as follows:

1. Methanol (CH3OH)
2. Ethanol (C2H5OH)
3. Propanol (C3H7OH)
4. Butanol (C4H9OH)

Forst four members of homologous series of carboxylic acids beginning with CH3COOH are as follows:

1. Ethanoic acid (CH3COOH )
2. Propanoic acid (C2H5COOH)
3. Butanoic acid (C3H7COOH)
4. Pentanoic acid (C4H9COOH)

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