Question

First , I had taken the wrong points , now I know that I had been mistaken ,I want to rectify it
Distance from O to t (Ot) = Ov+vu+ut
= 2+2+1=5
Similarly, distance from S to t (St)= Sz+zo+ot
= 2+2+1=5
Total distance from S to O
= St+Ot
=5+5
=10

Now displacement is tye the shortest distance possible which is SO (as the hypotenuse of the ∆OtS)
Applying Pythagoras theorem over ∆OtS
SO²=Ot²+St²
=>SO =√(5²+5²) = √(25+25)=√50or 5√2
Therefore SO=5√2
Displacement=5√2 {you can use value of
√2=1.414
then 5√2 = 7.07
and Distance =10
....
Hope it helps

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Answer 1

Answer:

First , I had taken the wrong points , now I know that I had been mistaken ,I want to rectify it

Distance from O to t (Ot) = Ov+vu+ut

= 2+2+1=5

Similarly, distance from S to t (St)= Sz+zo+ot

= 2+2+1=5

Total distance from S to O

= St+Ot

=5+5

=10

Now displacement is tye the shortest distance possible which is SO (as the hypotenuse of the ∆OtS)

Applying Pythagoras theorem over ∆OtS

SO²=Ot²+St²

=>SO =√(5²+5²) = √(25+25)=√50or 5√2

Therefore SO=5√2

Displacement=5√2 {you can use value of

√2=1.414

then 5√2 = 7.07

and Distance =10

....

Hope it helps

Explanation:

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