Question

First number is 14.28% more than third number and second number is 16.67 % more than third number then second number is how much percent more than first number?

Answer 1

$Let \: 3rd \: no \: is \: 100 \\ </p><p>So \: 1st \: no \: is \: 114.28 \\ </p><p>2nd \: no \: is \: 116.27 \\ </p><p></p><p>So \: required \: answer \: is \: \frac{116.27 - 114.28}{114.2} \times 100 \\ = 1.75\% \: or \: nearly \: equal \: to \: 1.8\%$

Answer 2

Second number is 2.09% more than first number

Step-by-step explanation:

Let the third number be x

We are given that First number is 14.28% more than third number

So, First number =$x+\frac{14.28}{100}x=\frac{114.28}{100}x$

Second number is 16.67 % more than third number

Second number =$x+\frac{16.67}{100}x=\frac{116.67}{100}x$

We are supposed to find  second number is how much percent more than first number?

Difference between second number and first number =$\frac{116.67}{100}x-\frac{114.28}{100}x=\frac{2.39}{100}x$

So,second number is percent more than first number =$\frac{\frac{2.39}{100}x}{\frac{114.28}{100}x} \times 100=2.09\%$

Hence Second number is 2.09% more than first number

#Learn more:

If 16.67℅ of a number is 125, find the number?

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