First number is 45% less than third number, second number is 20% more than third number
then average of first two numbers is how much percent less than third number?
Answers
Answer:
12.5%
Step-by-step explanation:
We let the 3 numbers be x, y, and z
We know that the first number is 45% less than the third so our list is:
0.55z, y, z
Since the second number is 20% more than the third number our list becomes
0.55x, 1.2z, z
The average of the first 2 are
(1.2z + 0.55z)/2 = 0.875z
We use the percent change formula
(new number-old number)/old number x 100
Our old number is z and our new number is 0.875z
Solving this gets -12.5, since the sign is negative, we know that this means percent decrease so 12.5% decrease
Answer:
Let the third number be 100
Step-by-step explanation: According to question
Third number is 100
First number is 100-100*45/100= 100-45=55
Second number is 100+100*20/100= 100+20=120
Average of the first number and second number
= 55+120/2=175/2=87.5
Required Percentage Less:- 100-87.5/100*100
=12.5%