Question

First of all,

4x = 98² - 88²

4x = (98+88)(98-88). {a^2-b^2 = (a+b)(a-b) or (a-b)(a+b)}.

4x = (186)(10).

4x = 1860.

x = 1860/4.

x = 465

Answer 1

Answer࿐

Find two consecutive odd numbers such that two fifths of the smaller number exceeds two ninths of the larger by 4

Solution :

Let one odd number be ' 2n + 1 '

This is smallest odd number .

Other consecutive odd number be ' 2n + 3 '

This is largest odd number .

A/c , " Two fifths of the smaller number exceeds two ninths of the larger by 4 "

First consecutive smallest odd number :

= 2n + 1

= 2(12) + 1

= 24 + 1

= 25

Second consecutive largest odd number :

= 2n + 3

= 2(12) + 3

= 24 + 3

= 27

Alternative : You may solve this question by taking ' x ' as smallest consecutive odd number and ' x + 2 ' as biggest consecutive odd number .

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Answer 2

Answer:

Answer: 465. 4x = (98+88)(98-88). {a^2-b^2 = (a+b)(a-b) or (a-b)(a+b)}.

Step-by-step explanation:

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