Chemistry, asked by riaz56771, 1 year ago

first order rate constant for decomposition of N2O4 is 6.2*10^-4 per sec. half period for this decomposition is

Answers

Answered by Anonymous
0
1117.7 sec. is the answer
Answered by S0HINI
5
t 1/2 => 0.693/ 62×10^-4
=====> 1117.7 sec...Ans✔
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