Question

first order reaction plot of logK Vs1/T gives straight line. The slop of line has been found to be - 8.95 x 10-3 'K. The activation energy for the reaction is ---​

Answer 1

Answer:

Activation Energy = 171.3669209 * 10⁻³ J

Explanation:

We Have :-

$Slope=-8.95*10^{-3} K$

To Find :-

Activation Energy

Formula Used :-

$Slope =\frac{-Activation\ Energy}{2.303\ R}$

Solution :-

$Slope = \frac{-Ea}{2.303\ R} \\\\-8.95*10^{-3} = \frac{-Ea}{2.303*8.314} \\\\Ea = 8.95*10^{-3} * 2.303 * 8.314\\\\Ea = 171.3669209 * 10^{-3} J$