Question

first order reaction take 40 min for 30% completion what is t/2
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Answer 1

Answer:

Let a M be the initial concentration. After 40 minutes, the concentration is a−

30a/100=0.70a

k= 2.303/t

k= 2.303/40 log  [a]/[a]

k=8.92x10 - 3/per min

The half life period, t= 1/2=0.693/k=  0.693/8.92x10-3/min= 77.7

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Explanation:

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